Question

How do you find two missing sides of a right triangle with a right angle and a 50 degree angle, the hypotenuse is 2√2?

Answer 1

Missing sides are `2.17(2dp), 1.82(2dp)`units

Explanation:

Let hypotenuse of right triangle is `c=2sqrt2`. Base of right triangle is `a` and perpendicular of right triangle is `b` and angle between sides `a and c` is `/_B=50^0 ; sinB=b/c or sin50=b/(2sqrt2) or b=2sqrt2sin50=2.17(2dp)`

`cosB=a/c or cos50=a/(2sqrt2) or a=2sqrt2 cos50 =1.82(2dp)`

Missing sides are `2.17(2dp), 1.82(2dp)` units [Ans]