Question

How do you find vector parametric equation for the line through the point P=(−4,−5,3) perpendicular to the plane 3x−4y+3z=−1?

Answer 1

`vecr=(-4,-5,3)+t(3,-4,3)`

Explanation:

The vector normal to the plane is `vecn=(3,-4,3)`
The point P is `vecr_o=(-4,-5,3)`
Equation is `vecr=r_o +tvecn`
So the equation of the line is `vecr=(-4,-5,3)+t(3,-4,3)`