How do you get a initial and terminal point given #x=cos(pi-t)#, #y=sin (pi-t)#, #0<=t<=1#?

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Answer 1 · 2017-07-20T01:41:20

The start and end points are:

# (-1,0) # and # (-0.54,0.84) #

respectively

We have parametric equations:

# x = cos(pi-t) #
# y = sin (pi-t) # where #0<=t<=1#

For the start point we take #t=0#:

# x = cos(pi) =-1#
# y = sin (pi) = 0#

For the end point we take #t=1#:

# x = cos(pi-1) ~~ -0.54#
# y = sin (pi-1) ~~ 0.84#

Thus the start and end points are:

# (-1,0) # and # (-0.54,0.84) #

respectively, which represents a small arc of a circle in Q2