How do you graph #-6x+9y=-18#?

1 Answer
Nov 23, 2016

#-6x+9y=-18#

This is a linear equation, because the equation does not have any exponents. Graph it by putting the equation into either slope-intercept form #y=mx+b# or point-slope form #y-y_1=m(x-x_1)#.

Isolate y by first adding 6x to each side:
#9y=6x-18#

Divide each side by 9:
#y=2/3x-2#

Now graph the line #y=2/3x-2# by first plotting the y intercept at #(0,-2)#, then connecting points with a slope of #2/3#.

graph{2/3x-2 [-10, 10, -5, 5]}