How do you graph #r=1/((cos t)^2)#?

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Answer 1 · 2016-07-01T09:11:21

#1 <=r< oo#,.

As #t to pi/2 or (3pi)/2, r to oo#.

The graph is symmetrical about #theta=0, pi/2. pi and (3pi)/2# (both x and y axes)

Rightly, the graph is asymptotic to these directions and the radial

lines #theta=pi/2 and theta=(3pi)/2# (y-axis, both ways) are not

asymptotes.

The graph cuts the initial line #theta=0# at (1, 0).

Elsewhere, #r>1.#.

The graph looks like a hyperbola, near the pole..