Question

How do you graph `r=2+costheta`?

Answer 1

The graph is r-oscillation, withe period `2pi`, about the circle r = 2, in the range `r in [1, 3]`..

Explanation:

The Table for one period, for `theta = 0 (pi/4) 2pi`::

`(r, theta): (3, 0) (2+1/sqrt 2, pi/4) (2, pi/2) (2-1/sqrt 2, 3/4pi)`

`(1, pi) (1+1/sqrt 2, 5/4pi) (2, 3/2pi) (2+1/sqrt 2, 5/4pi) (3, 2pi)`1,