# How do you graph #r=2+sin theta#?

##### 1 Answer

In

#### Explanation:

The Table for one period #theta in [0, 2pi] is sufficient.

Altogether this graph is a wave, twining around a circle.

graph{x^2 + y^2 - 2sqrt(x^2 + y^2) - y = 0}

Credit for the graphs goes to Socratic.

graph{(x^2 + y^2)^1.5 - 2(x^2 + y^2) - 2xy = 0}

The second graph is for

graph{(x^2 + y^2)^2 - 2(x^2 + y^2)^1.5 - 3(x^2y-xy^2) = 0}

The third is for

graph{(x^2 + y^2)^2.5 - 2(x^2 + y^2)^2 -4(x^3y-xy^3) = 0}

The fourth is for