Question

How do you graph `r=-3sintheta`?

Answer 1

See graph.
graph{x^2+y^2+3y=0 [-8, 8, -4, 4]}

Explanation:

As `r(costheta, sintheta)=(x,y)`,

`r^2=x^2+y^2=-3rsintheta=-3y`, giving

`x^2+(y+3/2)^2=(3/2)^2` representing the circle,

with center `C(0, -3/2)` and radius `a = 3/2`.

Now, make Socratic graph

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