# How do you graph #r=4+7sintheta#?

##### 1 Answer

Jul 4, 2018

See graph and details.

#### Explanation:

Using

Here,

As

initial line

Graph of the limacon

graph{ x^2 + y^2 - 4 sqrt ( x^2 + y^2 ) -7 y = 0[-14 14 -2 12]}

This limacon, with the characteristic dimple, is the member n = 1 of

the multiloop family

= 2 and 7.

graph{ (x^2+y^2)^1.5- 4(x^2+y^2)-7xy=0[-24 24 -12 12]}

graph{ (x^2+y^2)^4 - 4(x^2+y^2)^3.5 -7(x^7-21x^5y^2+35x^3y^4-7xy^6)=0[-24 24 -12 12]}