How do you graph #r=6+6costheta#?

1 Answer
Oct 11, 2016

graph{6+6cos x [-14.13, 14.36, -1.17, 15]}

Explanation:

Hopefully you know what the graph of #y=cos theta# looks like:
graph{cos x [-14.13, 14.36, -7.17, 7.05]}

The the graph of #y=6cos theta# is that graph stretched along Oy by factor 6:
graph{6cos x [-14.13, 14.36, -7.17, 7.05]}

Finally, the graph of #y=6+6cos theta# is that graphed moved up alonmg Oy 6 units
graph{6+6cos x [-14.13, 14.36, -1.17, 15]}