Question

How do you graph the equation `-5x+3y=10`?

Answer 1

`y=5/3 x + 10/3`

So you start at the y-intercept, and then go up 5 units and right 3 units.

Explanation:

`-5x+3y=10`

Isolate y to get the slope-intercept form `y=mx+b`
`3y = 5x +10`

`y=5/3 x + 10/3`
So now you have the slope `m = 5/3` and the y-intercept `(0, 10/3)`.

You can get the slope-intercept if you let `x=0` and then the equation `y=5/3 (0) + 10/3` gets you `y=10/3`

The slope `m = 5/3` means to go up 5 units and then go right 3 units.

So you start at the y-intercept and make a point, and then go up 5 units and right 3 units and make a point. Then simply make a straight line because it's a linear equation.

graph{5/3 x + 10/3 [-10, 10, -5, 5]}