# How do you graph the equation -5x+3y=10?

Jul 24, 2017

$y = \frac{5}{3} x + \frac{10}{3}$

So you start at the y-intercept, and then go up 5 units and right 3 units.

#### Explanation:

$- 5 x + 3 y = 10$

Isolate y to get the slope-intercept form $y = m x + b$
$3 y = 5 x + 10$

$y = \frac{5}{3} x + \frac{10}{3}$
So now you have the slope $m = \frac{5}{3}$ and the y-intercept $\left(0 , \frac{10}{3}\right)$.

You can get the slope-intercept if you let $x = 0$ and then the equation $y = \frac{5}{3} \left(0\right) + \frac{10}{3}$ gets you $y = \frac{10}{3}$

The slope $m = \frac{5}{3}$ means to go up 5 units and then go right 3 units.

So you start at the y-intercept and make a point, and then go up 5 units and right 3 units and make a point. Then simply make a straight line because it's a linear equation.

graph{5/3 x + 10/3 [-10, 10, -5, 5]}