How do you graph the equation 5x+3y=10?

1 Answer
Jul 24, 2017

y=53x+103

So you start at the y-intercept, and then go up 5 units and right 3 units.

Explanation:

5x+3y=10

Isolate y to get the slope-intercept form y=mx+b
3y=5x+10

y=53x+103
So now you have the slope m=53 and the y-intercept (0,103).

You can get the slope-intercept if you let x=0 and then the equation y=53(0)+103 gets you y=103

The slope m=53 means to go up 5 units and then go right 3 units.

So you start at the y-intercept and make a point, and then go up 5 units and right 3 units and make a point. Then simply make a straight line because it's a linear equation.

graph{5/3 x + 10/3 [-10, 10, -5, 5]}