# How do you graph the lines using slope-intercept form #y = -2/3x + 1#?

##### 1 Answer

See a solution process below:

#### Explanation:

This equation is in slope intercept form. The slope-intercept form of a linear equation is:

Where

Therefore, the y-intercept is:

We can plot this point on the grid as:

graph{(x^2 + (y-1)^2 - 0.025) = 0 [-10, 10, -5, 5]}}

The slope is:

Slope is also:

In this case, the

This second point is:

We can now plot this point:

graph{(x^2 + (y - 1)^2 - 0.025)((x - 3)^2 + (y + 1)^2 - 0.025) = 0 [-10, 10, -5, 5]}}

Now, we can draw a line through the two points giving:

graph{(y + (2/3)x - 1)(x^2 + (y - 1)^2 - 0.025)((x - 3)^2 + (y + 1)^2 - 0.025) = 0 [-10, 10, -5, 5]}}