# How do you graph the polar equation #r=1.5theta#?

##### 1 Answer

Polar equations vary *counterclockwise* through from

#r = 1.5theta#

This equation has

Here, with

For example, if you look at

#r = 1.5 xx pi/2 ~~ ul2.35# on the vertical axis.

If we pass through

#r = 1.5 xx (pi/2 + pi/2) => ul(-4.71)# on the horizontal axis

If we pass through

#r = 1.5 xx (pi/2 + pi) => ul(-7.07)# on the vertical axis.

If we pass through

#r = 1.5 xx (pi/2 + (3pi)/2) ~~ ul9.42# on the horizontal axis.

Then, if we pass through

#r = 1.5 xx (pi/2 + 2pi) ~~ ul11.78# on the vertical axis.

Once you have those major points, connect them in a spiral.