How do you graph using slope and intercept of #-1x - 6y = 4#?

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Answer 1 · 2017-06-02T16:54:03

See below.

#y=mx+b#

where #m# is the slope and #b# is the y-intercept.

#-1x-6y=4#

Add #1x# to both sides of the equation.

#-6y=4+x#

#6y=-x-4#

Divide both sides of the equation by #6#.

#y=(-1/6)x-4/6#

So this line has slope of #-1/6# and a y-intercept of #-2/3#.

graph{y= (-1/6)x-2/3 [-10, 10, -5, 5]}