# How do you graph using slope and intercept of  x-3y= -13?

May 15, 2018

$y = \frac{1}{3} x + \frac{13}{3}$ graph{1/3x+13/3 [-20, 20, -10, 10]}

#### Explanation:

The slope-intercept form is $y = m x + b$ therefore we have to isolate the $y$.

Begin by subtracting $x$ from both sides to get $- 3 y = - x - 13$ (since $x$ is positive on the left.)

Next, divide both sides by $- 3$ to get $y = \frac{1}{3} x + \frac{13}{3.}$

Graph by using $\frac{13}{3}$ on the $y$- intercept and the using a rise of $1$ and a run of $3$ to find the next point.