# How do you graph Y= 3(x - 2)^2 + 5?

Dec 13, 2017

Check this out

#### Explanation:

graph{3*(x-2)^2+5 [-2, 10, 4.08, 20]}

Assume values for x. Calculate values for y and plot
Let us take x values 0,1,2,3,4. Then
If $x = 0$ then $y = 3 {\left(0 - 2\right)}^{2} + 5 = 17$
If $x = 1$ then $y = 3 {\left(1 - 2\right)}^{2} + 5 = 8$
If $x = 2$ then $y = 3 {\left(2 - 2\right)}^{2} + 5 = 5$
If $x = 3$ then $y = 3 {\left(3 - 2\right)}^{2} + 5 = 8$
If $x = 4$ then $y = 3 {\left(4 - 2\right)}^{2} + 5 = 17$

Now plot $\left(0 , 17\right) , \left(1 , 8\right) , \left(2 , 5\right) , \left(3 , 8\right) , \left(4 , 17\right)$