How do you graph #y=3tan(2x+pi/2)-2#?

1 Answer
Apr 12, 2018

Answer:

As below.

Explanation:

Standard form of equation is #y = A tan (Bx - C) + D#

Given equation is #y = 3 tan (2x + (pi/2)) -2 #

#Amplitude = |A| = " None " " for tangent"#

#"Period " = pi / |B| = pi / 2#

#"Phase Shift " = (-C) / B = (-(pi/2)) / 2 = -pi/4, " " pi/4 " to the left"#

#"Vertical Shift " = D = -2#

graph{3 tan(2x + (pi/2)) - 2 [-10, 10, -5, 5]}