How do you graph # y>4x+2# and ##?

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May 11, 2018

Answer:

graph{y>4x+2 [-10, 10, -5, 5]}

Explanation:

First, graph the line. The line is in #y=mx+b# form and #mx# is the Slope and #b# is the y-intercept. Since the slope is #4#, the lines goes up by #4# for every x-value. Since the y-intercept is #2#, it can be written as #(0,2)#, which is the point that the line touches when the x-value is #0#.
graph{y=4x+2 [-10, 10, -5, 5]}
However, we are graphing an inequality so we need to change the line to a dotted or solid one and shade either the top or the bottom. The inequality that you provided claims that #y# is greater than #4x+2#. Since it's greater than, the top will be shaded. It doesn't say greater than or equal to so the line will be dotted. I hope this helps.
graph{y>4x+2 [-10, 10, -5, 5]}

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