# How do you graph y=csc(2*theta+π)-3?

Mar 11, 2018

As below.

#### Explanation:

Standard form of equation for csc is $y = a \csc \left(b \theta - c\right) + d$

$y = \csc \left(2 \theta + \pi\right) - 3$

Period = (2pi) / |b| = (2pi) / 2 = pi

Phase shift = c / b = -pi / 2 = -pi/2 color(white)(aaa)pi/2 to the left.

Vertical shift $= d = - 3$

graph{csc (2x + pi) - 3 [-10, 10, -5, 5]}