# How do you graph y = sin(x - π/4) + 2?

Jun 6, 2018

As below.

#### Explanation:

$y = \sin \left(x - \left(\frac{\pi}{4}\right)\right) + 2$

Standard Form of a sine function is $y = A \sin \left(B x - C\right) + D$

$\therefore A = 1 , B = 1 , C = \frac{\pi}{4} , D = 2$

$A m p l i t u \mathrm{de} = | A | = 1$

Period $= \frac{2 \pi}{|} B | = 2 \pi$

Phase Shift $= - \frac{C}{B} = \frac{\pi}{4}$, $\frac{\pi}{4}$ to the right#

Vertical Shift $= D = 2$

graph{sin(x-(pi/4)) + 2 [-10, 10, -5, 5]}