# How do you integrate int root3(x^2)dx?

By the Power Law: $\frac{3}{4} {x}^{\frac{4}{3}}$
$\sqrt[3]{{x}^{2}} = {x}^{\frac{1}{3}}$. Hence using the Power Law ($\int {x}^{n} \mathrm{dx} = \frac{1}{n + 1} {x}^{n + 1} + c , n \ne 0$) you get $\frac{1}{\frac{1}{3} + 1} {x}^{\frac{1}{3} + 1} + c$