Question

How do you multiply `e^(( 13pi )/ 12 ) * e^( pi/2 i )` in trigonometric form?

Answer 1

`e^((13pi)/2)/_(13pi)/2`

Explanation:

From Euler's formula we get that

`e^(i(pi/2))=cos(pi/2)+isin(pi/2)=i`.

`therefore e^((13pi)/2)*e^(i(pi/2))=ie^((13pi)/2`

`=e^((13pi)/2)/_(13pi)/2`