How do you simplify #5 sqrt48- 8 sqrt 27#?

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Answer 1 · 2016-07-22T05:25:19

#5sqrt48-8sqrt27=-4sqrt3#

#5sqrt48-8sqrt27#

= #5sqrt(2xx2xx2xx2xx3)-8sqrt(3xx3xx3)#

= #5sqrt(ul(2xx2)xxul(2xx2)xx3)-8sqrt(ul(3xx3)xx3)#

Take the squared numbers outside of the square root

= #5xx2xx2xxsqrt3-8xx3xxsqrt3#

= #20sqrt3-24sqrt3#

= #-4sqrt3#