Question

How do you simplify `sin^-1 (cos ((7pi)/6))`?

Answer 1

`sin^(-1)(cos((7pi)/6))=-pi/3`

Explanation:

As `cos((7pi)/6)=cos(pi+pi/6)=-cos(pi/6)`

= `-sin(pi/2-pi/6)=-sin(pi/3)=sin(-pi/3)`

Hence, `sin^(-1)(cos((7pi)/6))=-pi/3`