How do you sketch the curve #f(x)=1/(1+x^2)# by finding local maximum, minimum, inflection points, asymptotes, and intercepts?
1 Answer
Dec 20, 2016
Explanation:
as # x to +-oo, y to 0. S0,
the global maximum is the y-intercept ( x = 0 ) 1.
At x =0,
#=2(x^2-1)/(1+x^2)^3=0, when x = +-1. y here = 1/2.
y''' is not 0, when
So,
graph{y(x^2+1)-1=0 [-2.5, 2.5, -1.25, 1.25]}