How do you sketch the curve #y=x^3+6x^2+9x# by finding local maximum, minimum, inflection points, asymptotes, and intercepts?
1 Answer
Jan 18, 2017
See graph and explanation
Explanation:
Polynomial graphs have no asymptotes.
As x to +-oo, y = x^3(1+3/x)^2 to +-oo, showing end behavior of
So, there are no global extrema.
x-intercepts:
Turning points or points of inflexion at (-1, -4) and (-3, 0)
At
This POI is marked, in the graph.
At
At
graph{(x(x+3)^2-y)((x+2)^2+(y+2)^2-.01)=0 [-10, 10, -10, 5]}