How do you solve #14-x=3x-2#?

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Answer 1 · 2016-07-08T14:58:27

#x = 4#

For problems like this you want to get the variable on one side of the equation and your constants ( a number on its own) on the other side.

Put your variables on the right side of the equation by adding x on both sides. You should end up with:

#14 = 4x-2#

Add 2 on both sides of the equation so the constants are on the left side leaving 4x on the right and 16 on the left:

#16 = 4x#

Divide both sides by 4 to solve for x:

#16/(4) = (4x)/(4)#

#x=4#