# How do you solve 2(x+1)=0?

Dec 1, 2016

$x = - 1$

#### Explanation:

Step 1) Expand the term in parenthesis:

$2 \cdot x + 2 \cdot 1 = 0$

2x + 2 = 0#

Step 2) Subtract $2$ from each side of the equation to isolate the $x$ term and keep the equation balanced:

$2 x + 2 - 2 = 0 - 2$

$2 x + 0 = - 2$

$2 x = - 2$

Step 3) Divide each side by $2$ to solve for $x$ while keeping the equation balanced:

$\frac{2 x}{2} = \frac{- 2}{2}$

$\frac{\cancel{2} x}{\cancel{2}} = - 1$

$x = - 1$