How do you solve #-2/(x-10)<0# using a sign chart?

1 Answer
Mar 3, 2017

Answer:

The answer is #x in ]10,+oo[#

Explanation:

We rearrange the equation

#-2/(x-10)<0#

#2/(x-10)>0.#

Let #f(x)=2/(x-10#

The time chart is

#color(white)(aaaa)##x##color(white)(aaaa)##-oo##color(white)(aaaaaaa)##10##color(white)(aaaaaaa)##+oo#

#color(white)(aaaa)##x-10##color(white)(aaaa)##-##color(white)(aaaa)##||##color(white)(aaaa)##+#

#color(white)(aaaa)##f(x)##color(white)(aaaaaa)##-##color(white)(aaaa)##||##color(white)(aaaa)##+#

Therefore,

#f(x>0)#, when #x in ]10,+oo[#