How do you solve 2x^3-5x^2<2x-5?

Aug 12, 2016

$x \in \left(- 1 , 1\right)$.
${x}^{2} \left(2 x - 5\right) < \left(2 x - 5\right)$
factor, ${x}^{2} < 1$. So, $| x | < 1.$.