# How do you solve 2x^3-5x^2<2x-5?

Aug 12, 2016

$x \in \left(- 1 , 1\right)$.

#### Explanation:

${x}^{2} \left(2 x - 5\right) < \left(2 x - 5\right)$

To preserve the inequality sign, 2x-5 is not 0. Canceling this

factor, ${x}^{2} < 1$. So, $| x | < 1.$.