How do you solve $3x^2<5x$ using a sign chart?

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Answer 1 · 2018-01-01T15:21:52

Solution: $0 < x < 5/3 or (0,5/3)$

$3x^2 <5x or 3x^2-5x < 0 or x(3x-5)< 0$

Critical points are $x=0 and 3x-5=0 or x=5/3$

Sign chart:

When $x< 0$ sign of $x(3x-5)$ is $(-) * (-)= (+) ; > 0$

When $0 < x < 5/3$ sign of $x(3x-5)$ is

$(+) * (-)= (-) ; < 0$

When $x > 5/3$ sign of $x(3x-5)$ is $(+) * (+) = (+) ; > 0$

Solution: $0 < x < 5/3 or (0,5/3)$

How do you solve 3x^2<5x3x^2<5x using a sign chart?