# How do you solve 3x-3=6x+1?

Dec 30, 2016

$x = - \frac{4}{3}$

#### Explanation:

If we collect the terms in x on the left side of the equation and numeric values on the right side.

subtract 6x from both sides.

$3 x - 6 x - 3 = \cancel{6 x} \cancel{- 6 x} + 1$

$\Rightarrow - 3 x - 3 = 1$

$- 3 x \cancel{- 3} \cancel{+ 3} = 1 + 3$

$\Rightarrow - 3 x = 4$

To solve for x, divide both sides by - 3

$\frac{\cancel{- 3} x}{\cancel{- 3}} = \frac{4}{- 3}$

$\Rightarrow x = - \frac{4}{3} \text{ is the solution}$