# How do you solve 4x^2 <(12x-9)?

Sep 2, 2016

$4 {x}^{2} < 12 x - 9$ does not have any solution.

#### Explanation:

$4 {x}^{2} < 12 x - 9$

$\Leftrightarrow 4 {x}^{2} - 12 x + 9 < 0$ or

(2x)^2-2×2x×3+3^2<0 or

${\left(2 x - 3\right)}^{2} < 0$ i.e. (2x-3 is negative.

But a square number can not be negative.

Hence $4 {x}^{2} < 12 x - 9$ does not have any solution.