How do you solve #6/x+2>=0#?

1 Answer
Apr 20, 2017

Answer:

#x>0# and #x leq -3#

Explanation:

Notice that this inequality is defined for #xne 0#.

By simple calculation we reduce to the form we need to study:

#1/xgeq -1/3#

so if #x>0# it is always true.

Let #x<0#, so multiplying by #x# affects the sign:

#1/xgeq -1/3 Leftrightarrow 1leq-1/3x Leftrightarrow -3 geq x#