How do you solve #6(x+8)=18#?

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Answer 1 · 2018-03-02T02:17:53

the answer is #x=-5#

#6x+48=18#
#-48#
#6x=-30#
divide #6# from both sides
#x=-5#

Answer 2 · 2018-03-02T02:17:58

No need to expand the brackets in the first step
Simply transfer the 6
#x+8=18/6#
#x+8=3#
Transfer 8
#x=3-8#
#x=-5#

Answer 3 · 2018-03-02T02:19:14

#x=-5#

Apply the Distributive Property on the left side, which tells us that #a(b+-c)=ab+-ac#

#6(x+8)=18hArr6x+6(8)=18#

Simplifying, we have

#6x+48=18#

We now want to isolate #x.# Subtract #48# from both sides:

#6xcancel(+48-48)=18-48#

#6x=-30#

Divide both sides by #6:#

#(cancel6x)/cancel6=-30/6#

#x=-5#