How do you solve #8p-2p+3=10p-6#?

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Answer 1 · 2016-08-06T07:26:07

#p=9/4#

To solve a linear equation like #16-2.4d=-8#, we should all constant terms to one side and variable term to other side. Thus

#8p-2p+3=10p-6# or

#8p-2pul(-10p-3)+3=10pul(-10p-3)-6# or

#8p-2p-10p-cancel3+cancel3=cancel(10p)-cancel(10p)-3-6# or

#8p-2p-10p=-3-6# or

#(8-2-10)p=-9# or

#-4p=-9# i.e.

#p=(-9)/(-4)=9/4#