Question

How do you solve and graph `x^2+25<10x`?

Answer 1

There is no real solution,

Explanation:

To solve `x^2+25-10x<0`, we find that:

`x^2+25-10x=(x+-5)^2- or+ 10x to (x-5)^2>=0`

So, there is no real solution.

I tried in vain to invoke a Socratic graph that could illustrate my

conclusion.