How do you solve and graph #x^2+25<10x#?

1 Answer
Jan 2, 2017

Answer:

There is no real solution,

Explanation:

To solve #x^2+25-10x<0#, we find that:

#x^2+25-10x=(x+-5)^2- or+ 10x to (x-5)^2>=0#

So, there is no real solution.

I tried in vain to invoke a Socratic graph that could illustrate my

conclusion.