# How do you solve for a in  SA=2ab+2ac+2bc ?

Feb 15, 2016

Put the terms that contain a's alone on one side of the equation and factor out the a.

#### Explanation:

$S A - 2 b c = 2 a b + 2 a c$

$S A - 2 b c = 2 a \left(b + c\right)$

$\frac{S A - 2 b c}{b + c} = 2 a$

$\frac{S A - 2 b c}{2 b + 2 c} = a$

Practice Exercises:

1. Solve for x

a) $2 x y + 3 y z = 5 x y z - 4 y$

b) $\sqrt{3 x + 2 y} = 2 x - 4 x z$

Good luck!