How do you solve for x in 3x-q=5q?

Apr 28, 2016

$x = 2 q$

Explanation:

As $3 x - q = 5 q$, adding $= q$ on both sides, we get

$3 x - \cancel{q} + \cancel{q} = 5 q + q$

or $3 x = 6 q$, now multiplying both sides by $\frac{1}{3}$, we get

$\cancel{3} x \times \frac{1}{\cancel{3}} = 2 \cancel{6} q \times \frac{1}{\cancel{3}}$

or $x = 2 q$