How do you solve #\frac{8}{x + 4} \geq \frac{1}{x + 4}#?

1 Answer
Sep 24, 2016

Answer:

Solution is #x > -4#

Explanation:

It is apparent that the denominator cannot take the value #0# and hence #x+4!=0# or #x!=-4#.

If it is so, then #8/(x+4)>=1/(x+4)#

if #x+4>0# then multiplying both side by it #8/(x+4)>=1/(x+4)hArr8>=1# or #8>=1#, which is true.

if #x+4<0# then multiplying both side by it #8/(x+4)>=1/(x+4)hArr8<=1# or #8<=1#, which is false.

Hence Solution is #x+4>0# or #x > -4#