# How do you solve sqrt(2x-7)>=5?

Feb 4, 2017

$x \ge 16$

#### Explanation:

Square both sides

${\left(\sqrt{2 x - 7}\right)}^{2} \ge {5}^{2}$

$2 x - 7 \ge 25$

Add $7$ to both sides

$2 x \ge 32$

Divide both sides by $2$

$x \ge 16$