# How do you solve sqrt(m+2)<sqrt(3m+4)?

Aug 14, 2017

$m > - 1$.

#### Explanation:

If we square both sides, we can get:

${\left(\sqrt{m + 2}\right)}^{2} < {\left(\sqrt{3 m + 4}\right)}^{2}$

$m + 2 < 3 m + 4$

$- 2 m < 2$

We now divide both sides by $- 2$, not forgetting to switch the direction of the inequality symbol.

$m > - 1$

We now test our answer to see if it is true. Let $m = 1$.

sqrt(3) < sqrt(7) color(green)(√)

This is obviously true.

Hopefully this helps!