# How do you solve t(2t+3)+20=2t(t-3)?

t = -2.2222..., or t = $- \frac{20}{9}$
In this equation, we would first distribute the t through the (2t + 3), and distribute the 2t through the (t - 3). After doing so, you get, $2 {t}^{2} + 3 t + 20 = 2 {t}^{2} - 6 t$. Next, we would combine like terms getting,
$9 t + 20 = 0$, where the two $2 {t}^{2}$'s cancel each other out. Next, move the 20 to the other side, $9 t = - 20$. Finally, divide both sides by 9 to separate the t. Your final answer should be either, t = -2.2222..., or
t = $- \frac{20}{9}$.