# How do you solve the inequality 4x^2+20x+25>=0?

Jan 16, 2017

The inequality is true for all values of $x$
$4 {x}^{2} + x + 25 \ge 0$
$\left(2 x + 5\right) \left(2 x + 5\right) \ge 0$
${\left(2 x + 5\right)}^{2} \ge 0$