How do you solve the right triangle ABC given b=2, A=8?

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Answer 1 · 2018-05-03T15:26:35

#c = 2 sqrt 17 approx 8.25 # cm

#a^2 + b^2 = c^2#

In which c is always the longest line in the triangle which is the hypotenuse of the triangle.

Assuming that the A and b that you stated are the opposite and the adjacent, we can substitute it in the formula.

Substitution

#8^2 + 2^2 = c^2#

This gives you:

#c^2 = 68#

To solve for c,

#c = sqrt68 = 2 sqrt 17#

#c approx 8.25 # cm

If angles are provided, you can use the sine, cosine or tangent rule.