Question

How do you solve the right triangle if a=3.0cm, b=2.6cm, C=90°?

Answer 1

Assuming your notation matches the image below
the side with length `c` is given by the Pythagorean Theorem

`c^2 = a^2+b^2`
`c=sqrt(a^2+b^2) = sqrt((3.0)^2+(2.6)^2) = 3.97 "(approx.)"`

Angle `A = arctan((3.0)/(2.6))`
and
Angle `B = arctan((2.6)/(3.0))`
(you'll need to look these up in a table or use a calculator)