How do you solve #x-4=8+3x#?
1 Answer
Apr 24, 2016
Explanation:
To solve the given problem, you want to move all variables with
In your case, move all terms with
Starting with,
#x-4=8+3x#
Subtract
#x# #color(red)(-x)-4=8+3x# #color(red)(-x)#
#-4=8+2x#
Subtract
#-4# #color(red)(-8)=8# #color(red)(-8)+2x#
#-12=2x#
Divide both sides by
#color(red)(color(black)(-12)/2)=color(red)(color(black)(2x)/2)#
#color(green)(|bar(ul(color(white)(a/a)x=-6color(white)(a/a)|)))#