# How do you solve #x-4=8+3x#?

##### 1 Answer

Apr 24, 2016

#### Explanation:

To solve the given problem, you want to move all variables with

In your case, move all terms with

Starting with,

#x-4=8+3x#

Subtract

#x# #color(red)(-x)-4=8+3x# #color(red)(-x)#

#-4=8+2x#

Subtract

#-4# #color(red)(-8)=8# #color(red)(-8)+2x#

#-12=2x#

Divide both sides by

#color(red)(color(black)(-12)/2)=color(red)(color(black)(2x)/2)#

#color(green)(|bar(ul(color(white)(a/a)x=-6color(white)(a/a)|)))#