How do you solve x-4=8+3x?

Apr 24, 2016

$x = - 6$

Explanation:

To solve the given problem, you want to move all variables with $x$ to one side of the equation and all other terms without $x$ to the other.

In your case, move all terms with $x$ to the right side and the ones without to the left.

Starting with,

$x - 4 = 8 + 3 x$

Subtract $x$ from both sides,

$x$ $\textcolor{red}{- x} - 4 = 8 + 3 x$ $\textcolor{red}{- x}$

$- 4 = 8 + 2 x$

Subtract $8$ from both sides,

$- 4$ $\textcolor{red}{- 8} = 8$ $\textcolor{red}{- 8} + 2 x$

$- 12 = 2 x$

Divide both sides by $2$,

$\textcolor{red}{\frac{\textcolor{b l a c k}{- 12}}{2}} = \textcolor{red}{\frac{\textcolor{b l a c k}{2 x}}{2}}$

$\textcolor{g r e e n}{| \overline{\underline{\textcolor{w h i t e}{\frac{a}{a}} x = - 6 \textcolor{w h i t e}{\frac{a}{a}} |}}}$