# How do you solve #(x-4)(x+3)<0# using a sign chart?

##### 1 Answer

#### Answer:

#### Explanation:

Find the critical points. Equate the "factors" to 0 to get the critical points. Use 0 as a critical point also.

The critical points are

Now, pick a number that lies in each region (in-between/on either side of these critical points), plug it into each factor, and find the *sign* of each factor in each region. You'll make a table like this one.

The last row is just the *product* of the two rows above it.

Also, since we manually added 0 as a critical point, we calculate

#(0-4)(0+3)" "=" "("-"4)(3)" "=" ""-"12" "<" "0#

Based on this and the chart above,