How do you write an equation of a line with slope 1 and y-intercept 1?

2 Answers
Nov 20, 2016

Answer:

#y=x+1#

Explanation:

Equation of a line with slope #m# and #y#-intercept #c# is

#y=mx+c#

and hence equation of a line with slope #1# and #y#-intercept as #1# is

#y=1xxx+1# or #y=x+1#
graph{y=x+1 [-5.938, 4.06, -2.12, 2.88]}

Nov 20, 2016

Answer:

#y=x+1#

Explanation:

The equation of a line in #color(blue)"slope-intercept form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=mx+b)color(white)(2/2)|)))#
where m represents the slope and b, the y-intercept.

Here m = 1 and b = 1

#rArry=x+1" is the equation of the line"#