How do you write an equation of the line with slope=5 passing through point (-8,2) in standard form?

1 Answer
Jun 13, 2018

Answer:

#5x-y=-42#

Explanation:

use point slope form first, because you are given a point and a slope:
#y-y_1=m(x-x_1)#
which is:
#y-2=5(x+8)#
Then convert to slope intercept form by distributing the 5 and adding over the 2:
#y=5x+42#
Then subtract the y and 42 to the opposite sides to convert it to standard form:
#5x-y=-42#